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Question 145
If $$sin\theta + \sin^2\theta = 1$$, then the value of cos12$$\theta$$ + 3cos10$$\theta$$ + cos6$$\theta$$ + Â 3cos8$$\theta$$Â - 1Â is
Solution
Given equation can be written as $$(cos^4\theta + cos^2\theta)^3 -1$$
as $$sin\theta + sin^2\theta = 1$$
or $$sin\theta = cos^2\theta$$
putting above value in given equation it will be
$$(sin^2\theta + sin\theta)^3 -1 = 0$$
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