Question 144

The geometric mean of the observations 1, 4, 9, 27, 256 is

Solution

G.M. of the given observations = $$\sqrt[\ 5]{\left(1\right)\left(4\right)\left(9\right)\left(27\right)\left(256\right)}$$

$$=\sqrt[\ 5]{1\times2^2\times3^2\times3^3\times2^8}$$

$$=\sqrt[\ 5]{2^{10}\times3^5}$$

$$=2^2\times3$$

$$=12$$

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