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Question 144
From a point P on a level ground, the angle of elevation of the top of a tower is $$30^\circ$$. If the tower is 270 m high. the distance of point P from the foot of the tower is:
Solution
Given, Height of the tower = 270 m
Let the distance from the foot of the tower to P be x m
tan 30 = $$\dfrac{AB}{BP}$$
$$\dfrac{1}{\sqrt{3}} = \dfrac{270}{x}$$
$$x = 270\sqrt{3} = 270\times1.732 = 467.65 m$$
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