Question 143
A copper wire of length 36 m and diameter 2 mm is melted to form a sphere. The radius of the sphere (in cm) is:
Solution
since we know volume will remain same while melting
$$\pi r_{1}^{2}h= \frac{4}{3}\pi r_{2}^{3}$$
where $$r_{1}$$ is radius of cylinderical wire and $$r_{2}$$ is radius of sphere and h is length of wire
putting values we will get $$r_{2}$$ = 3 cm.
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