Question 141

The value of $$(sin^{2} 25^{\circ} + sin^{2} 65^{\circ})$$ is :

Solution

the given equation is $$(sin^{2} 25^{\circ} + sin^{2} 65^{\circ})$$

we know that $$sin^{2} 25^{\circ}$$ = $$sin^2(90-65)$$ = $$cos^265$$

So, $$(sin^{2} 25^{\circ} + sin^{2} 65^{\circ})$$ = $$cos^2$$65+ $$sin^{2} 65$$

and we know that $$sin^2 \theta + cos^2 \theta $$ = 1

Hence $$cos^265$$+ $$sin^{2} (65)$$ = 1

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