Question 141

The number $$142^{2}-1$$ is divisible by

Solution

Number = $$(142)^{2}-(1)^2$$

Using, $$a^2-b^2=(a-b)(a+b)$$

= $$(142-1)(142+1)$$

= $$141\times143$$

= $$(3\times47)\times(11\times13)$$

Thus, it is divisible by 13.

=> Ans - (C)


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