Question 140
ΔBCD is parallelogram. P and Q are the mid-points of sides BC and CD respectively. If the area of .6, ABC is 12 cm , then the area of ΔAPQ is
Solution
△APQ = $$\frac{3}{8}\times ABCD$$
= $$\frac{3}{8}\times 2 ABC$$
= $$\frac{3}{8}\times 12$$
= 9
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