Question 140

ΔBCD is parallelogram. P and Q are the mid-points of sides BC and CD respectively. If the area of .6, ABC is 12 cm , then the area of ΔAPQ is

Solution

△APQ = $$\frac{3}{8}\times ABCD$$
= $$\frac{3}{8}\times 2 ABC$$
= $$\frac{3}{8}\times 12$$
= 9

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

Free SSC Study Material - 18000 Questions
230+ SSC previous papers with solutions PDF
100+ SSC Online Tests for Free

Follow us on

Boost your Prep!

Download App