Question 14

A small point mass carrying some positive charge on it, is released from the edge of a table. There is a uniform electric field in this region in the horizontal direction. Which of the following options then correctly describe the trajectory of the mass? (Curves are drawn schematically and are not to scale)

Given: $$u = 0$$

$$F_x = qE \implies a_x = \frac{qE}{m}$$

$$F_y = -mg \implies a_y = -g$$

$$x = \frac{1}{2}a_x t^2 = \frac{qE}{2m}t^2$$

$$y = -\frac{1}{2}gt^2$$

$$\frac{y}{x} = -\frac{mg}{qE} = \text{constant} \implies y = mx$$

Other Cracku’s Useful Resources:

JEE Questions JEE Question Bank JEE Mains Previous Papers JEE Advanced Previous Papers JEE Study Material PDF JEE Mains Mock Test JEE Advanced Mock Test JEE Daily Target

JEE Physics Questions JEE Maths Questions JEE Chemistry Questions