Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A force $$\vec{F} = (5\hat{i} + 3\hat{j} + 2\hat{k})N$$ is applied over a particle which displaces it from origin to the point $$\vec{r} = (2\hat{i} - \hat{j})$$ m. The work done on the particle in joules is
Create a FREE account and get:
Educational materials for JEE preparation