The value of x which satisfies the equation $$2 \csc^{2} 30^{\circ}+x \sin^{2}60^{\circ}-\frac{3}{4}\tan^{2}30^{\circ}=10$$ is
Remember that
sin 60° = √3/2
cosec 30° = 1/sin 30° = 1/(1/2) = 2
tan 30° = 1/√3
the given equation becomes
2·(2^2) + (3/4) x - (3/4) (1/3) = 10
8 + (3/4) x - 1/4 = 10
multiply by 4
32 + 3x - 1 = 40
3x = 9
x=3
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