Question 139

The centroid of an equilateral triangle ABC is G and AB=10 cm. The length of AG (in cm)

Solution

G is the centroid of $$\triangle$$ ABC and AB = 10 cm.

Also, a centroid divides the median in the ratio = $$AG : GD = 2 : 1$$

Now, median AD = $$\frac{\sqrt3}{2}\times10=5\sqrt3$$ cm

$$\therefore$$ AG = $$\frac{2}{(2+1)}\times5\sqrt3$$

= $$\frac{10\sqrt3}{3}$$ cm

=> Ans - (B)

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