TS ICET 24th May 2019 Shift-1

Question 138

Let P be an external point to a circle and PT be a tangent drawn from P meeting the circle at 7. If AB is a chord ofthe circle such that A, B, P are collinear, PT = 5 cm and PB = 4 cm then PA =

Solution

Using tangent secant theorem,

$$PT^{2 }$$=PA$$\times\ $$PB

5$$\times\ $$5=PA$$\times\ $$4

PA=$$\ \frac{25}{ 4}$$=6.25


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