Question 138

If x + y = 15, then $$(x-10)^{3}+(y-5)^{3}$$ is

Solution

given that x + y = 15

So reaaranging the above equation

(x -10 ) + (y-5) =0

Now , x-10 =-( y -5 )

On cubing both sides

$$(x-10)^3$$ =- $$(y-5)^3$$

And hence

$$(x-10)^3$$ + $$(y-5)^3$$ =0

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