Question 138

I. $$x^{2}+3x-28=0$$
II. $$y^{2} -y-20=0$$

Solution

I.$$x^{2} + 3x - 28 = 0$$

=> $$x^2 + 7x - 4x - 28 = 0$$

=> $$x (x + 7) - 4 (x + 7) = 0$$

=> $$(x - 4) (x + 7) = 0$$

=> $$x = 4 , -7$$

II.$$y^{2} - y - 20 = 0$$

=> $$y^2 - 5y + 4y - 20 = 0$$

=> $$y (y - 5) + 4 (y - 5) = 0$$

=> $$(y + 4) (y - 5) = 0$$

=> $$y = -4 , 5$$

$$\therefore$$ No relation can be established.


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