Question 135
In a right-angled triangle ABC, ∠ABC = 90°, AB = 5 cm and BC = 12 cm. The radius of the circumcircle of the triangle ABC is
Solution
In $$\triangle$$ABC
=> AC = $$\sqrt{(AB)^2 + (BC)^2}$$
=> AC = $$\sqrt{5^2 + 12^2}$$ = $$\sqrt{169}$$
=> AC = 13 cm
In a right angled triangle, circumcentre lies on the mid point of hypotenuse.
=> circumradius = $$\frac{AC}{2}$$ = $$\frac{13}{2}$$ = 6.5 cm
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