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Question 134
Walking at 5 km/hr a student reaches his school from his house 15 minutes early and walking at 3 km/hr he is late by 9 minutes. What is the distance between his school and his house?
Solution
Let the time and distance be t mins and d respectively,
In the first case:
Total time taken = (t - 15) mins = (t-15)/60 hrs.
Distance travelled = 5*(t-15)/60
In the second case:
Total time taken = (t + 9) mins = (t+9)/60 hrs.
Distance travelled = 3*(t+9)/60
So, 5*(t-15)/60 = 3*(t+9)/60,
Solving the above equation we get, t=51
So, d=3*(51+9)/60
        =3 KMs
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