Sign in
Please select an account to continue using cracku.in
↓ →
In a special racing event, the person who enclosed the maximum area would be the winner and would get Rs 100 for every square meter of area covered by him/her. Johnson, who successfully completed the race and was the eventual winner, enclosed the area shown in figure below. What is the prize money won? (Note: The arc from C to D makes a complete semi-circle).
AB = 3 m, BC = 10 m, CD = BE = 2 m
Total area of figure = ar(semi circle) + ar(rectangle BCDE) + ar(triangle ABE)
= $$\frac{\pi}{2} (r)^2 + (BC\times CD)+(\frac{1}{2}\times AB\times BE)$$
= $$1.57 \times(1)^2 + (10\times 2)+(\frac{1}{2}\times 3\times 2)$$
= $$1.57 + 20+3=24.57$$ $$m^2$$
$$\therefore$$ Total amount won $$100\times24.57=Rs.$$ $$2457$$
=> Ans - (B)
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation