Question 133
If the operation ‘o’ among real numbers is defined by x o y = $$x^2 - 2y$$, then values of x satisfying 2xo 4 =2 ox is
Solution
It is given that $$x o y = x^2 - 2y$$
$$\therefore$$ $$2x o 4 = 4x^2 - 8$$
and $$2 o x = 4 - 2x$$
=> $$4x^2 - 8 = 4 - 2x$$
=> $$2x^2 + x - 6 = 0$$
=> $$2x^2 + 4x - 3x - 6 = 0$$
=> $$2x (x + 2) - 3 (x + 2) = 0$$
=> $$(2x - 3) (x + 2) = 0$$
=> $$x = \frac{3}{2} , -2$$
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