Solution
Given : $$(3x^{2}-9x+3)=0$$
=> $$(3x^{2}+3)=9x$$
Dividing both sides by $$'3x'$$, we get :
=> $$x+\frac{1}{x}=3$$ -------------(i)
Cubing both sides,
=> $$(x+\frac{1}{x})^3=(3)^3$$
=> $$(x+\frac{1}{x})^3=27$$
=> Ans - (D)
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