Question 132

An equilateral triangle of side 6cm has its corners cut off to form a regular hexagon. Area (in cm2) of this regular hexagon will be ?

Solution

The hexagon is composed of 6 equilateral triangles, each with a side of 2.

Area of an equilateral triangle = $$\frac{\sqrt3}{4}s^2$$

=> Area of regular hexagon = 6 $$\times$$ area of small equilateral triangles

= $$6\times\frac{\sqrt3}{4}\times(2)^2$$

= $$6\sqrt3$$ $$cm^2$$

=> Ans - (C)

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