8 litres of water is added to 32 litres of a solution containing 20% of alcohol in water. What is the approximate concentration of alcohol in the solution now ?
In 32 litres of solution, quantity of alcohol = $$\frac{20}{100}\times32=6.4$$ litres
=> Quantity of water = $$32-6.4=25.6$$ litres
On adding 8 litres of water, total solution = $$32+8=40$$ litres
=> Required % = $$\frac{(6.4)}{40}\times100=16\%$$
=> Ans - (B)
Create a FREE account and get:
Quick, Easy and Effective Revision
By proceeding you agree to create your account
Free CAT Formulae PDF will be sent to your email address soon !!!
