Question 130

What is the value of m in the quadratic equation $$x^{2}+mx+24=0$$ if one of its roots is $$\frac{3}{2}$$

Solution

Putting $$x=\frac{3}{2}$$ in the quadratic equation : $$x^{2}+mx+24=0$$

=> $$(\frac{3}{2})^2+m(\frac{3}{2})+24=0$$

=> $$\frac{9}{4}+24+\frac{3m}{2}=0$$

=> $$\frac{3m}{2}=-(\frac{96+9}{4})$$

=> $$m=\frac{-105}{4}\times\frac{2}{3}$$

=> $$m=\frac{-35}{2}$$

=> Ans - (D)

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