Question 130

The value of $$\frac{\sin30^\circ-\cos60^\circ+\cot^2 45^\circ}{\cos30^\circ-\tan 45^\circ+\sin 90^\circ}$$ is equal to:

Solution

we know that,

sin30=$$\frac{1}{2}$$. cos60=$$\frac{1}{2}$$ , cot45=$$1$$, cos30=$$\ \frac{\sqrt{\ 3}}{2}$$, sin90= $$1$$, tan45=$$1$$,

putting values into equation we get,

$$\frac{\left\{\frac{1}{2\ }-\frac{1}{2}+1^{2\ }\right\}}{\frac{\sqrt{\ 3}}{2}-1+1}\ =\frac{2\sqrt{\ }3}{3}\ ans$$

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