The marked price of an article is 60% more than its cost price. What maximum discount percentage can be offered by the shopkeeper to sell his article at no profit or no loss?
Let cost price = Rs. $$100x$$
Markup % = 60%
=> Marked price =Â $$100x+(\frac{60}{100}\times100x)=Rs.$$ $$160x$$
To have no profit/loss, => Selling price = Rs. $$100x$$
$$\therefore$$ Discount % = $$\frac{(160x-100x)}{160x}\times100$$
= $$\frac{600}{16}=37.5\%$$
=> Ans - (A)
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