Question 13

The marked price of an article is 60% more than its cost price. What maximum discount percentage can be offered by the shopkeeper to sell his article at no profit or no loss?

Solution

Let cost price = Rs. $$100x$$

Markup % = 60%

=> Marked price = $$100x+(\frac{60}{100}\times100x)=Rs.$$ $$160x$$

To have no profit/loss, => Selling price = Rs. $$100x$$

$$\therefore$$ Discount % = $$\frac{(160x-100x)}{160x}\times100$$

= $$\frac{600}{16}=37.5\%$$

=> Ans - (A)

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