In the trapezium ABCD the sides AB and CD are parallel. The value of $$\frac{sin \angle{BAC}}{sin \angle{BAD}}$$ is 

A

$$\frac{BC}{AD}$$

B

$$\frac{AB}{CD}$$

C

$$\frac{AC}{CD}$$

D

$$\frac{AD}{AC}$$

E

$$\frac{AC}{AD}$$