Examine the following statements:
I. Total productivity of pulses has gone down over the years
II. Maize is the most stable cereal in terms of productivity over the years
III. Percentage growth in area and quantity of production is highest in the case of Jowar during the entrie period.
Select the best option:

Productivity is defined as total production per hectare. 
Total productivity of pulses in the year 2006 = $$\frac{130+31+149+13+26+2}{799+124+1228+20+126+5}$$ = $$0.1524$$

Total productivity of pulses in the year 2007 = $$\frac{270+30+191+9+45+3}{751+101+1151+19+110+5}$$ = $$0.2564$$

Total productivity of pulses in the year 2008 = $$\frac{260+35+250+9+30+2}{725+102+1199+19+101+5}$$ = $$0.2724$$

We can see that clearly, Total productivity of pulses in the year 2008 > Total productivity of pulses in the year 2007 >Total productivity of pulses in the year 2006. Hence, statement I is incorrect. Hence, we can reject option A and B.

Productivity of Maize in the year 2006 = $$\dfrac{1102}{1004}$$ = 1.097

Productivity of Maize in the year 2007 = $$\dfrac{1116}{1020}$$ = 1.094

Productivity of Maize in the year 2008 = $$\dfrac{1182}{1101}$$ = 1.073

We can see that productivity is approximately same during the given period for Maize. Hence, statement II is correct. Therefore, we can reject option D.

Thus, we can say that option C is the correct answer.