Question 128

The value of $$\dfrac{4.669 \times 4.669 - 9 \times (0.777)^2}{(4.669)^2 + (2.331)^2 + 14(0.667)(2.331)}$$ is (1 - k), where k = ?

Solution

Expression : $$\dfrac{4.669 \times 4.669 - 9 \times (0.777)^2}{(4.669)^2 + (2.331)^2 + 14(0.667)(2.331)}$$

= $$\dfrac{4.669 \times 4.669 -  (2.331)^2}{(4.669)^2 + (2.331)^2 + 2(4.669)(2.331)}$$

Let $$x=4.669$$ and $$y=2.331$$

= $$\dfrac{x^2-y^2}{x^2+y^2+2xy}$$

= $$\dfrac{(x-y)(x+y)}{(x+y)^2}=\dfrac{x-y}{x+y}$$

= $$\dfrac{4.669-2.331}{4.669+2.331}=\dfrac{2.338}{7}=0.334$$

According to ques, => $$k=1-0.334=0.666$$

=> Ans - (A)

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