Question 128

If the height of a triangle is increased by 10% and base is decreased by 10%, then its area would be 198 sq-cm. What was the original area?

Solution

Let the base and height be b and h respectively. Hence, the original area is = 1/2*b*h. After changing the base and height, area= 1/2 * (0.9b) * (1.1h) = 0.99 (1/2*b*h) = 198 sq-cm
Hence, (1/2*b*h) = 198/0.99 = 200 sq-cm

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