\left(\begin{array}{c}2 & 6\\\ 1 & 3\end{array}\right)\left(\begin{array}{c}3 & -6\\\ -1 & 2\end{array}\right) =

Question 126

$$\left(\begin{array}{c}2 & 6\\ 1 & 3\end{array}\right)\left(\begin{array}{c}3 & -6\\ -1 & 2\end{array}\right) =$$

Solution

Solution:

$$\left(\begin{array}{c}2 & 6\\ 1 & 3\end{array}\right)\left(\begin{array}{c}3 & -6\\ -1 & 2\end{array}\right) =$$

let the resultant matrix be, $$\left(\begin{array}{c}A11 & A12\\ A21 & A22\end{array}\right)$$

A11 = 2.3 + 6.(-1) = 0

A12 = 2.(-6) + 6.(2) = 0

A21 = 1.3 +3.(-1) = 0

A22 = 1.(-6) + 3.2 = 0

= $$\left(\begin{array}{c}0 & 0\\ 0 & 0\end{array}\right)$$

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