Solution
Solution:
As on putting limit ,$$\lim_{x \rightarrow 3}$$ f(x) -> $$\frac{0}{0}\ format$$
So using L hospitals rule
Differentiating Nr and Dr. $$\lim_{x \rightarrow 3}$$ $$\frac{\left(3x^2\ -\ 6x\right)}{6x\ -\ 4}$$
Putting the limits,
$$\frac{\left(3x^2\ -\ 6x\right)}{6x\ -\ 4}\ =\ \frac{\left(3.3^2\ -\ 6.3\right)}{6.3\ -\ 4}=\ \frac{\left(27-18\right)}{14}=\ \frac{9}{14}$$
$$\ \frac{9}{14}$$ Answer
Get AI Help
Create a FREE account and get:
- Download Maths Shortcuts PDF
- Get 300+ previous papers with solutions PDF
- 500+ Online Tests for Free
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Session:Free CAT Mentorship
Phone:
Date:
Time:
Enter OTP
Didn't receive the OTP?
