Solution
Since, AB = BC
=> $$\angle$$A = $$\angle$$C = $$(2x-20)^{\circ}$$
In $$\triangle$$ABC
=> $$\angle$$A + $$\angle$$B + $$\angle$$C = 180°
=> $$(2x-20) + x + (2x-20) = 180^{\circ}$$
=> $$5x = 220$$
=> $$x = 44^{\circ}$$
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