Question 126

In a ΔABC, AB = BC, ∠B = x° and ∠A = (2x- 20)°. Then ∠B is

Solution

Since, AB = BC

=> $$\angle$$A = $$\angle$$C = $$(2x-20)^{\circ}$$

In $$\triangle$$ABC

=> $$\angle$$A + $$\angle$$B + $$\angle$$C = 180°

=> $$(2x-20) + x + (2x-20) = 180^{\circ}$$

=> $$5x = 220$$

=> $$x = 44^{\circ}$$

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