If $$p = 99$$, then the value of $$p (p^{2} + 3p + 3)$$ is
$$p (p^{2} + 3p + 3)$$
=Â $$p^{3} + 3p^{2} + 3p$$
=Â $$p^{3} + 3p^{2} + 3p+1-1$$
=Â $$(p+1)^{3}-1$$
=Â $$(99+1)^{3}-1$$
=Â $$(100)^{3}-1$$
= $$1000000-1$$
= $$999999$$
so the answer is option D.
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