Solution
$$p (p^{2} + 3p + 3)$$
= $$p^{3} + 3p^{2} + 3p$$
= $$p^{3} + 3p^{2} + 3p+1-1$$
= $$(p+1)^{3}-1$$
= $$(99+1)^{3}-1$$
= $$(100)^{3}-1$$
= $$1000000-1$$
= $$999999$$
so the answer is option D.
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