Question 126
A number lock consists of 3 rings each marked with 10 different numbers. In how many cases the lock cannot be opened?
Solution
The total number of combinations = 10*10*10 = 1000 (There are 10-digits 0 to 9 on each ring)
Since there is only 1 right combination, the number of cases in which the lock cannot be opened = 1000-1=999
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