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Question 124
If $$C_r = ^{10}C_r$$, for $$0 \leq r \leq 10$$, then $$2C_0 + 3C_1 + 4C_2 + ......... + 11C_{10} =$$
Solution
Solution
$$2.^{10}C_0$$ +$$3.^{10}C_1$$ + $$4.^{10}C_2$$.....
=$$2.1\ +\ \frac{3.10!}{1!9!}\ +\frac{4.10!}{2!8!}\ +\frac{5.10!}{3!7!}$$
= 2 + 30 + 180 + 600...
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