$$(x+\frac{1}{2})^{2} = q^4$$ and x is the smallest natural number then the possible values of q are

A

$$\pm\frac{1}{3}$$

B

$$\pm\sqrt{\frac{3} {2}}$$

C

$$\pm\frac{2}{\sqrt{3}}$$

D

$$\pm\frac{1}{2}$$