Solution
=$$\frac{(3)^\frac{5n}{5}\times3^{2n+1}}{3^2n\times3^{n-1}}$$
=$$\frac{(3)^{3n+1}}{3^{3n-1}}$$
=$${(3)^{3n+1-3n+1}}$$
=$$(3)^{2}$$ = 9 (B)
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
