The value of $$\frac{(243)^\frac{n}{5}\times3^{2n+1}}{9^n\times3^{n-1}}$$ is
=$$\frac{(3)^\frac{5n}{5}\times3^{2n+1}}{3^2n\times3^{n-1}}$$
=$$\frac{(3)^{3n+1}}{3^{3n-1}}$$
=$${(3)^{3n+1-3n+1}}$$
=$$(3)^{2}$$ = 9 (B)
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