Question 120

If a and b be positive integers such that $$a^2-b^2 = 19$$, then the value of a is

Solution

$$a^2-b^2 = 19$$
19 is a prime number 
(a + b)(a - b) = 19 x 1
So a + b = 19
     a - b = 1
Adding both the equations we get 2a = 20
                                                   a = 10


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App