Find the equivalent resistance between point A and B

Step 1: Loop APQ

• Series: 5+5=10 Ω
• Parallel with 10 Ω

$$R_{AQ}​=\ \frac{\ 10\cdot10}{10\ +\ 10}​=5Ω$$

Step 2: Loop AQR

• Series: 5+5=10 Ω
• Parallel with 10 Ω

$$R_{AR}​=\ \frac{\ 10\cdot10}{10\ +\ 10}​=5Ω$$

Step 3: Loop ARS

• Series: 5+5=10 Ω
• Parallel with 10 Ω

$$R_{AS}​=\ \frac{\ 10\cdot10}{10\ +\ 10}​=5Ω$$

Step 4: Section ASB

• Series: 5+5=10 Ω
• Parallel with 10 Ω1

$$R_{AB}=\ \frac{\ 10\cdot10}{10\ +\ 10}​=5Ω$$

Final Answer:

RAB​=5Ω​