Solution
we need to find : $$sin^{2} θ + cosec^{2} θ$$
Given that :$$sin θ + cosec θ = 2$$
So squaring both sides
$$(sin θ + cosec θ )^2= (2)^2$$
$$ sin^2 \theta + cosec^2 \theta + 2sin \theta cosec \theta$$ = 4
$$ sin^2 \theta + cosec^2 \theta $$ = 4-2 = 2
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