Question 119

If $$sin θ + cosec θ = 2$$, then the value of $$sin^{2} θ + cosecs^{2} θ$$ is :

Solution

we need to find : $$sin^{2} θ + cosec^{2} θ$$

Given that :$$sin θ + cosec θ = 2$$

So squaring both sides

$$(sin θ + cosec θ )^2= (2)^2$$

$$ sin^2 \theta + cosec^2 \theta + 2sin \theta cosec \theta$$ = 4

$$ sin^2 \theta + cosec^2 \theta $$ = 4-2 = 2

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