Question 119
ABC is a triangle with AC = BC and ∠ABC = 50°. The side BC is produced to D so that BC = CD. ∠BAD is
Solution
Given : BC = AC = CD and $$\angle$$ABC = 50°
To find : $$\angle$$BAD = ?
Solution : Since, BC = AC, => $$\angle$$ABC = $$\angle$$CAB = 50°
=> $$\angle$$ACB = 180° - 100° = 80°
Also, $$\triangle$$ACD is isosceles
=> $$\angle$$CAD = $$\angle$$ADC
=> $$\angle$$ACB = 2$$\angle$$CAD
=> $$\angle$$CAD = 80°/2 = 40°
$$\therefore$$ $$\angle$$BAD = 50° + 40° = 90°
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