O is the circum centre of the triangle ABC with circumradius 13 cm. Let BC = 24 cm and OD is perpendicular to BC. Then the length of OD is.
Given , Cord BC = 24 , radius OB = 13 . D be the mid point of BC , then OD will be perpendicular to BC.
So, BOD forms a right triangle.
so, OD = $$\sqrt{OB^2-BM^2}$$
= $$\sqrt{13^2-12^2}$$
= 5
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