Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 118
O is the circum centre of the triangle ABC with circumradius 13 cm. Let BC = 24 cm and OD is perpendicular to BC. Then the length of OD is.
Solution
Given , Cord BC = 24 , radius OB = 13 . D be the mid point of BC , then OD will be perpendicular to BC.
So, BOD forms a right triangle.
so, OD = $$\sqrt{OB^2-BM^2}$$
= $$\sqrt{13^2-12^2}$$
= 5
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
