A man performs 2/15 of the total journey by train, 2/20 of remaining by bus and the remaining 10 km on foot. His total journey in km is
let the total journey be y km
as it is mentioned that the man performs 2/15 of the total journey by train, So, the remaining jounrney = $$\frac{13y}{15}$$
the man completed 2/20 by bus and hence the remaining journey after this = $$\frac{18 \times 13y}{15 \times 20}$$ = $$\frac{39y}{50}$$
It is given that $$\frac{39y}{50}$$ = 10 Km
y = 12.8 km
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