A train crosses a platform in 30 seconds travelling with a speed of 60 km/h. If the length of the train be 200 metres, then the length (in metres) of the platform is
Let the length of train and speed of train be L meter and S m/sec . let the length of platform be P meter
It is given that L = 200 m
Time (T) = 30sec
S = 60 x $$\frac{5}{18}$$ = $$\frac{50}{3}$$ m /sec
using ,
(L+P) = S x T
(200 + P) = $$\frac{50}{3}$$ x 30
P = 300 m
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