Question 116

The sides of a triangular park are 35 m, 53 m and 66 m. The cost of levelling the park at the rate of ₹9.25/ m$$^2$$ is:

Solution

Sides of the triangle = 35,53,66

Semi perimeter = $$s=\frac{35+53+66}{2}=77$$ m

Area of triangle according to Heron's formula = $$\sqrt{s(s-a)(s-b)(s-c)}$$

= $$\sqrt{77(77-35)(77-53)(77-66)}$$

= $$\sqrt{77\times42\times24\times11}$$

= $$\sqrt{7^2\times11^2\times6^2\times4}$$

= $$7\times11\times6\times2=924$$ $$m^2$$

$$\therefore$$ Cost of levelling the park = $$9.25\times924=Rs.$$ $$8,547$$

=> Ans - (B)

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