Question 114

Three candidates "A", "B", "C" participated in an election. "A" gets 40% of the votes more than "B". "C" gets 20% votes more than "B". "A" also overtakes "C" by 4000 votes. If 90% voters voted and no invalid or illegal votes were cast, then what will be the number of voters in the voting list?

Solution

Let 100x be the total numbers of voters in the voters list. => 90x voters voted

A=1.4B (since A received 40% more votes than B)

C=1.2B

Given A-C = 4000

1.4B-1.2B=4000 => B=20000 => A=24000 and C = 28000

So total voter who voted =A+B+C= 72000 which is 90% of the total list.

So when 90%= 72000 , 100%= 80000.

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