Question 114

Three candidates "A", "B", "C" participated in an election. "A" gets 40% of the votes more than "B". "C" gets 20% votes more than "B". "A" also overtakes "C" by 4000 votes. If 90% voters voted and no invalid or illegal votes were cast, then what will be the number of voters in the voting list?

Solution

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Let 100x be the total numbers of voters in the voters list. => 90x voters voted

A=1.4B  (since A received 40% more votes than B)

C=1.2B


Given A-C = 4000

1.4B-1.2B=4000  => B=20000 => A=24000 and C = 28000

So total voter who voted =A+B+C= 72000 which is 90% of the total list.

So when 90%= 72000 , 100%= 80000.

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