Question 114

The area of circle whose radius is the diagonal of a square whose area is 4 is:

Solution

Side of square whose area is 4 units = $$\sqrt4=2$$ units

=> Radius of circle = Diagonal of square = $$\sqrt{(2)^2+(2)^2}=2\sqrt2$$ units

$$\therefore$$ Area of circle = $$\pi r^2$$

= $$\pi(2\sqrt2)^2=8\pi$$

=> Ans - (D)

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