Solution
Side of square whose area is 4 units = $$\sqrt4=2$$ units
=> Radius of circle = Diagonal of square = $$\sqrt{(2)^2+(2)^2}=2\sqrt2$$ units
$$\therefore$$ Area of circle = $$\pi r^2$$
= $$\pi(2\sqrt2)^2=8\pi$$
=> Ans - (D)
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