If x = 27 and $$\sqrt[3]{x} + \sqrt[3]{y} = \sqrt[3]{729}$$, the y =
as x = 27
$$\sqrt[3]{x}$$ = 3
we need to find $$\sqrt[3]{x} + \sqrt[3]{y} = \sqrt[3]{729}$$
3 + $$\sqrt[3]{y}$$ = 9
y = 216
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