Three ordinary coins having only two sides, namely, heads and tails are tossed in the air and two of such tossed coins land with tails facing upwards.
Determine that what are the chances on the next toss of the coins, at least two of the coins will land with the tails facing upwards ?
Solution
When tossing 3 coins, each coin has 2 possibilities (H or T). The total number of possible outcomes is 2^3 = 8.
The sample space (S) is:
HHH
HHT
HTH
THH
HTT
THT
TTH
TTT
The condition is "at least two" tails, which means we are looking for outcomes with exactly 2 tails or exactly 3 tails.
Exactly 2 tails: {HTT, THT, TTH} — 3 outcomes
Exactly 3 tails: {TTT} — 1 outcome
Total favorable outcomes = 3 + 1 = 4
Hence:
P(Atleast 2 tails) = 4/8 = 1/2 = 50%
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