The four digit number $$8ab9$$ is a perfect square. The value of $$a^2 + b^2$$ is

Solution

A square ending in 9 between 8009 and 8999 must have a root ending in 3 or 7, and checking values in that range, $$93^2=8649$$ is the only fit. So $$a=6$$, $$b=4$$, giving $$a^2+b^2=36+16=52$$.

Get AI Help

Other Cracku’s Useful Resources:

JEE Questions JEE Question Bank JEE Mains Previous Papers JEE Advanced Previous Papers JEE Study Material PDF JEE Mains Mock Test JEE Advanced Mock Test JEE Daily Target

Free JEE Questions

JEE Physics Questions JEE Maths Questions JEE Chemistry Questions

50,000+ JEE Students Trusted Our Score Calculator

Predict your JEE Main percentile, rank & performance in seconds

Check Your Score Now

Ask our AI anything

AI can make mistakes. Please verify important information.