Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 11
In $$\triangle ABC$$, D is a point on side BC such that $$\angle ADC = \angle BAC$$. If CA = 12 cm, CB = 8 cm, then CD is equal to:
Solution
$$\angle ADC = \angle BAC$$
$$\angle ACB = \angle ACD$$
So, $$\triangle$$ ABC ~ $$\triangle$$ DCA,
So, $$\frac{BC}{AC} = \frac{AC}{CD}$$
$$\frac{8}{12} = \frac{12}{CD}$$
CD = 144/8 = 18 cm
$$\therefore$$ The correct answer is option C.
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
