Question 11

In $$\triangle ABC$$, D is a point on side BC such that $$\angle ADC = \angle BAC$$. If CA = 12 cm, CB = 8 cm, then CD is equal to:

Solution

$$\angle ADC = \angle BAC$$
$$\angle ACB = \angle ACD$$
So, $$\triangle$$ ABC ~ $$\triangle$$ DCA,
So, $$\frac{BC}{AC} = \frac{AC}{CD}$$
$$\frac{8}{12} = \frac{12}{CD}$$
CD = 144/8 = 18 cm
$$\therefore$$ The correct answer is option C.

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SSC CGL Tier-2 11th September 2019 Maths

In $$\triangle ABC$$, D is a point on side BC such that $$\angle ADC = \angle BAC$$. If CA = 12 cm, CB = 8 cm, then CD is equal to:

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